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Question

Figure (10-E4) shows two blocks of masses m and M connected by a string passing over a pulley. The horizontal table over which the mass m slides is smooth. The pulley has a radius r and moment of inertia I about its axis and it can freely rotate about this axis. Find the acceleration of the mass M assuming that the string does not slip on the pulley.

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Solution

According to the equation

MgT1=Ma ...(1)

T2=ma ...(2)

(T1T2)=Iar2 [Because a = ra]....(3)

If we add the equation (1) and (2), we will get

Mg+T2T1 = Ma+ma ...(4)

MgIar2=Ma+ma

(M+m+Ir2)a=Mg

a=MgM+m+Ir2


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