Question

Figure 24-Q1 shows graphs of pressure vs density for an ideal gas at two temperatures $T_1$ and $T_2$.

• A. $T_1>T_2$
• B. $T_1=T_2$
• C. $T_1<T_2$
• D. Any of the three is possible.

Answer 1

The correct option is A $T_1>T_2$

Pv = nRT (ideal gas epn)
n = no of moles = $\frac{m}{M}$
Pv = $\frac{m}{M}$ RT
P = $\frac{m}{v}\frac{RT}{M}$
P = $\rho \frac{RT}{M}$
$ϵ\frac{y=mx}{misslope}$
$T_1>T_{2}i.e.m_1>m_2$
Thus, Option (a)