Figure represents a part of a closed circuit. The potential difference between points $C$ and $D$ $(V_{C} - V_{D})$ is:

+ 9 V

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- 9 V

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+ 1 V

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+ 6 V

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Solution

The correct option is C $+ 1 V$
Potential difference across $2 Ω$ resistance $= 2 T_{1}$
$= 2 \times 2$
$= 4 V$
Potential difference across $1 Ω$ resistance $= \frac{4}{1} - 3$
$= 4 - 3$
$= + 1 V$
Hence, the answer is $+ 1 V .$

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Figure represents a part of a closed circuit. The potential difference between points C and D (VC−VD) is:

The correct option is C +1VPotential difference across 2Ω resistance =2T1 =2×2 =4VPotential difference across 1Ω resistance =41−3 =4−3 =+1VHence, the answer is +1V.

Figure represents a part of a closed circuit. The potential difference between points $C$ and $D$ $(V_{C} - V_{D})$ is:

The correct option is C $+ 1 V$
Potential difference across $2 Ω$ resistance $= 2 T_{1}$
$= 2 \times 2$
$= 4 V$
Potential difference across $1 Ω$ resistance $= \frac{4}{1} - 3$
$= 4 - 3$
$= + 1 V$
Hence, the answer is $+ 1 V .$