Question

Figure shows a potentiometer arrangement. D is driving cell and C is the cell whose EMF is to be determined. AB is the potentiometer wire and G is galvanometer. J is jockey, then for balance condition of galvonometer

• A. EMF of D must be greater than EMF of C
• B. Positive terminals of D and C may be joined
• C. Negative terminals of D and C may be joined
• D. Positive terminal of D and negative terminal of C may be joined

Answer 1

Answer: (A), (B), (C)

The correct options are
A EMF of D must be greater than EMF of C
B Positive terminals of D and C may be joined
C Negative terminals of D and C may be joined

From the diagram, either of the conditions should be satisfied
1) $V_A<V_J<V_B$ or
2) $V_A>V_J>V_B$
These conditions imply, $|V_{AB}|>|V_{AJ}|$.
One of these conditions will be satisfied in all the options except option (4).