Figure shows a wooden block at rest in equilibrium on a rough horizontal plane being acted upon by forces $F_{1} = 10 N, F_{2} = 2 N$ as shown. If $F_{1}$ is removed, the resultant force acting on the block will be:

2 N

towards left

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2 N

towards right

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0 N

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cannot be determined

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Solution

The correct option is C $0 N$
As $F_{1} = 10 N > F_{2} = 2 N$ , the resultant motion of the block on the right. As the plane surface is rough so there is a friction force $f$ which is acting against the motion of the block.
In equilibrium resultant force is zero. Thus, $R = F_{1} - F_{2} - f = 0 \Rightarrow 10 - 2 - f = 0$
$∴ f = 8 N$
when $F_{1}$ is removed, the block can not move because the friction is greater than $F_{2}$ . So, the resultant should be zero.

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Figure shows a wooden block at rest in equilibrium on a rough horizontal plane being acted upon by forces F1=10N,F2=2N as shown. If F1 is removed, the resultant force acting on the block will be:

Figure shows a wooden block at rest in equilibrium on a rough horizontal plane being acted upon by forces $F_{1} = 10 N, F_{2} = 2 N$ as shown. If $F_{1}$ is removed, the resultant force acting on the block will be: