Question

Figure shows an incident ray AO and the normal ON a plane mirror. The angle which the incident ray AO makes with the mirror is ${30}^{\circ }$. (a) Find the angle of incidence. (b) Draw the reflected ray and then find the angle between the incident and reflected rays.

Answer 1

(a) Angle of incidence = 90^o – 30^o = 60^o
(b) Angle between the incident ray and reflected ray = Angle of incidence + Angle of reflection
Angle of reflection = Angle of incidence = 60^o
Therefore, Angle between the incident ray and reflected ray = 60^o + 60^o = 120^o