Figure shows the graph of a car travelling with a uniform velocity of 20 m/s. The brakes are then applied and the car is uniformly retarded. It comes to rest in further 8 s. Use this graph to find the total distance travelled.

260 m

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100 m

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80 m

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180 m

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Solution

The correct option is D 180 m
Total displacement $=$ area of trapezium OCBA
$= (1 / 2) \times 20 m / s \times (5 s + 13 s)$
$= 180 m$
Here, displacement $=$ distance as it moves only in one direction.

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Figure shows the graph of a car travelling with a uniform velocity of 20 m/s. The brakes are then applied and the car is uniformly retarded. It comes to rest in further 8 s. Use this graph to find the total distance travelled.

The correct option is D 180 mTotal displacement = area of trapezium OCBA =(1/2)×20m/s×(5s+13s) =180 mHere, displacement = distance as it moves only in one direction.

The correct option is D 180 m
Total displacement $=$ area of trapezium OCBA
$= (1 / 2) \times 20 m / s \times (5 s + 13 s)$
$= 180 m$
Here, displacement $=$ distance as it moves only in one direction.