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Question

Figure shows two blocks A and B connected to an ideal pulley string system. In this system when bodies are released then: (neglect friction and take g=10ms2)

A
Acceleration of block A is 1 ms2
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B
Acceleration of block A is 2 ms2
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C
Tension in string connected to block B is 40 N
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D
Tension in string connected to block B is 80 N
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Solution

The correct option is D Tension in string connected to block B is 80 N

By length contrained
aP1=aA+aB2
ap1=0+ap22
ap2=2 ap1
Now ap2=ac+ap2
ap2=a10 kg+02
a10 kg=2ap2
a10 kg=4ap1=4a
For 40 kg
40g - 4T = 40 a...........(i)
For 10 kg
T = 10 (4a)..........(ii)
From (i) and (ii)
a=2ms2 and T=80N
So, correct answers are B and D

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