Figure shows two blocks A and B connected to an ideal pulley string system. In this system when bodies are released then: (neglect friction and take g=10ms2)
A
Acceleration of block A is 1 ms2
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B
Acceleration of block A is 2 ms2
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C
Tension in string connected to block B is 40 N
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D
Tension in string connected to block B is 80 N
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Solution
The correct option is D Tension in string connected to block B is 80 N
By length contrained aP1=aA+aB2 ⇒ap1=0+ap22 ∴ap2=2ap1
Now ap2=ac+ap2 ∴ap2=a10kg+02 ⇒a10kg=2ap2 ⇒a10kg=4ap1=4a
For 40 kg
40g - 4T = 40 a...........(i)
For 10 kg
T = 10 (4a)..........(ii)
From (i) and (ii) a=2ms2andT=80N
So, correct answers are B and D