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Thermal Equilibrium

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Question

Figure shows two flasks connected to each other. The volume of the flask 1 is twice that of flask 2. The system is filled with an ideal gas at temperature 100 K and 200 K respectively in the flasks. If the mass of the gas in 1 m, then what is the mass of the gas in flask 2 in equilibrium?

A

m

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B

\frac{m}{2}

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C

\frac{m}{4}

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D

\frac{m}{8}

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Solution

The correct option is B $\frac{m}{4}$
At equilibrium pressure in both the flasks must be same.

Using ideal gas equation;

$\frac{n_{1} R T_{1}}{V_{1}} = \frac{n_{2} {R T}_{2}}{V_{2}}$

$\frac{m_{1} \times 100 K}{{2 V}_{2}} = \frac{m_{2} \times 200 K}{V_{2}}$

$m_{2} = \frac{m}{4}$

So, the correct option is $C$

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