Question

Fill in the blank

$\left[\begin{array}{ccc}8& 6& 72\\ 5& 12& 90\\ 12& 9& \underset{–}{}\end{array}\right]$

Answer 1

When we observe the numbers in first two rows,

The third number in each row is one and half (or) $\frac{3}{2}$ times the product of the first two numbers.
i.e., the formula is : $\frac{3}{2}\times ab=c$

$8\times 6=48;\frac{3}{2}\times 48=72$
$5\times 12=60;\frac{3}{2}\times 60=90$
$12\times 9=108;\frac{3}{2}\times 108=162$

Hence, the required number is $162$.

$\left[\begin{array}{ccc}8& 6& 72\\ 5& 12& 90\\ 12& 9& \underset{–}{162}\end{array}\right]$