Question

Fill in the blank:

The standard form of $\frac{-21}{48}$ is ………..

Answer 1

Given rational number is $\frac{-21}{48}$.

Here numerator is $-21$ and denominator is $48$.

Prime factors of $21$ and $48$ are as follows:

$$\begin{gathered} 21=3\times 7 \\ 48=2\times 2\times 2\times 2\times 3 \end{gathered}$$

HCF of $21$ and $48$ is $3$.

Now divide the numerator and denominator of $\frac{-21}{48}$ by HCF $3$, we get:

$\frac{-21÷3}{48÷3}=\frac{-7}{16}$

Therefore the standard form of $\frac{-21}{48}$ is $\frac{-7}{16}$.