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Question

Fill in the blank with smallest digit to make 4...6837 divisible by11.


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Solution

Since as we know the difference between the sum of all digits at even or odd place is0 and multiple of 11.

Let the smallest digit x to make 4...6837 divisible by 11.

In 4x6837 , sum of all digits at odd place=4+6+3=13

sum of all digits at even place =x+8+7=x+15

difference of sum of all digits at odd place and even place x+15-13=x+2

If x=9 then 9+2=11 which is divisible by 11.

Hence, the smallest digit to be placed in blank space is 9 then the digit 9 to make 4...6837 divisible by 11.


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