Question

Fill in the blank with smallest digit to make $.......6724$ divisible by $3.$

Answer 1

Since as we know that sum of all digits of a number is divisible by$3$ then the number is divisible by $3.$

The sum of all digits of a number $x6724$ is $x+6+7+2+4=19+x$ where $x$ is the smallest digit.

When we $x=2$ then $19+2=21$which is divisible by $3.$

Hence, the smallest digit to be placed in blank space is $2$ then digit $2$ to make $.......6724$ divisible by $3.$