Question

Fill in the blank with smallest digit to make $6000.....3$ divisible by $3.$

Answer 1

Since as we know that sum of all digits of a number is divisible by$3$ then the number is divisible by $3.$

The sum of all digits of a number $6000x3$ is $6+0+0+0+3=x+9$ where $x$ is the smallest digit.

When we $x=0$ then $0+9=9$ which is divisible by $3.$

Hence, the smallest digit to be placed is blank space is $0$ then digit $0$ to make $6000.....3$ divisible by $3.$