Fill in the blanks:-

$6^{2}$ + $7^{2}$ + $($ __ $)^{2}$ = $43^{2}$

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Solution

6 and 7 are consecutive numbers

$6 \times 7 = 42$

So, $6^{2} + 7^{2} + 42^{2} = 43^{2}$

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Fill in the blanks: $6^{2}$ + $7^{2}$ + $($ ___ $)^{2}$ = $43^{2}$

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