The correct option is A 42 6 and 7 are consecutive numbers 6 × 7 = 42 6^2 + 7^2 + 42^2 = 43^2 ...

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Finding Square of a Number Using Identity

62+72+-2=432

Question

$6^{2}$ + $7^{2}$ + $($ ___ $)^{2}$ = $43^{2}$

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Solution

The correct option is A
42

6 and 7 are consecutive numbers

$6 \times 7 = 42 6^{2} + 7^{2} + 42^{2} = 43^{2}$

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Similar questions

$6^{2}$ + $7^{2}$ + $($ ___ $)^{2}$ = $43^{2}$

Fill in the blanks:-

$6^{2}$ + $7^{2}$ + $($ __ $)^{2}$ = $43^{2}$

Fill in the blanks: $6^{2}$ + $7^{2}$ + $($ ___ $)^{2}$ = $43^{2}$

Choose the right option for the blank.

$6^{2}$ + $7^{2}$ + $($ __ $)^{2}$ = $43^{2}$

6^{2} + 7^{2} +

= 43^{2}

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