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Question

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A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5 m/s2, the frictional force acting on the block is ........ Newtons.

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Solution

Given that,
mass =1 kg
Acceleration of truck =5 m/s2
force acting on block =m×a=1×5 N=5 N
coefficient of friction =0.6=μ
Maximum value can be given by =μmg
=0.6×1×10=6 N
Maximum friction will be 6 N
But friction will be 5 N

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