Question

Fill in the blanks by choosing the correct options.

• A. $X=6.023\times {10}^{23}$ moleccules$Y=22.4L$ at any pressure$Z=$ Gram molecular mass
• B. $X=6.023\times {10}^{23}$ atoms/moleccules$Y=22.4L$ at NTP$Z=$ Gram atomic mass
• C. $X=6.023\times {10}^{23}$ atoms$Y=22.4L$ at any temperature$Z=1$ gram mole
• D. $X=6.023\times {10}^{23}$ particles$Y=11.2L$ at NTP$Z=$ Molar volume

Answer 1

Answer: (B)

$X=6.023\times {10}^{23}$ atoms/moleccules

$Y=22.4L$ at NTP

$Z=$ Gram atomic mass

$1$ mole $=6.023\times {10}^{23}$ atoms / molecules $=X$

$1$ mole = Molar volume $=22.4L$ at $NTP$ $=Y$
$1$ mole = Gram atomic mass or gram molecular mass $=Z$

Hence, option $B$ is correct.