Question

Fill in the blanks with $>,<$ or $=$ in the following:

$\frac{-2}{3}\_\_\_\frac{-8}{12}$

Answer 1

Given : $\frac{-2}{3}\_\_\_\frac{-8}{12}$

First,convert them in equivalent fraction.

Take the LCM of the denominators.

So, LCM of $3$ and $12$ is $12$.

Now convert the given rational numbers in equivalent fraction with denominator $12$.

$\Rightarrow \frac{-2\times 4}{3\times 4}=\frac{-8}{12}$ and $\frac{-8\times 1}{12\times 1}=\frac{-8}{12}$

As, both the fractions are same, i.e., $\frac{-8}{12}=\frac{-8}{12}$

Hence, $\frac{-2}{3}=\frac{-8}{12}$.