Question

Fill in the blanks with the appropriate choice.
Bond order of $N_2^{+}$ is $P$ while that of $N_2$ is $O$. Bond order of $O_2^{+}$ is $R$ while that of $O_2$ is $S$. $N-N$ bond distance $T$, when $N_2$ changes to $N_2^{+}$ and when $O_2$ changes to $O_2^{+}$, the $O-O$ bond distance $U$.

• A. $P-2,Q-2.5,R-2.5,S-1,T-$ increases, $U-$ decreases
• B. $P-2.5,Q-3,R-2,S-1.5,T-$ decreases, $U-$ increases
• C. $P-3,Q-2,R-1.5,S-1,T-$ increases, $U-$ decreases
• D. $P-2.5,Q-3,R-2.5,S-2,T-$ increases, $U-$ decreases

Answer 1

The correct option is D $P-2.5,Q-3,R-2.5,S-2,T-$ increases, $U-$ decreases

$Bondorder=\frac{NumberofelectronsinBMO-NumberofelectronsinABMO}{2}$,

$N_2^{+}$	$13$ electrons	Bond order=$2.5$	$P$
$N_2$	$14$ electrons	Bond order=$3$	$Q$
$O_2^{+}$	$15$ electrons	Bond order=$2.5$	$R$
$O_2$	$16$ electrons	Bond order=$2$	$S$
$N-N$ changes to $N_2^{+}$ and $O_2$ changes to $O_2^{+}$	$3$ to $2.5$ and $2$ to $2.5$	Increase and decrease	$T$ and $U$

So the correct option is $D$.