Fill in the box: -15=12
Find the missing fraction:
Given, -15=12
Let the missing fraction be x.
Now,
x-15=12
⇒x=15+12
=2+510
⇒x=710
Hence, 710-15=12
{1(sec2θ−cos2θ)+1(cosec2θ−sin2θ)}(sin2θcos2θ)=1−sin2θcos2θ2+sin2θcos2θ
Determine whether the following numbers are in proportion or not:
13,14,16,17
loge(n+1)−loge(n−1)=4a[(1n)+(13n3)+(15n5)+...∞] Find 8a.