Question

Fill in the boxes: (a). ()$-\frac{5}{8}=\frac{1}{4}$, (b). $\left(\right)-\frac{1}{5}=\frac{1}{2}$, (c). $\left(\right)-\frac{1}{2}=\frac{1}{6}$

Answer 1

let boxes$=\frac{x}{y}$ then,

Solve part (a).

$\frac{x}{y}-\frac{5}{8}=\frac{1}{4}$

$\frac{x}{y}=\frac{1}{4}+\frac{5}{8}$

$\frac{x}{y}=\frac{2+5}{8}$

$\frac{x}{y}=\frac{7}{8}ans.$

Solve part (b).

$\frac{x}{y}-\frac{1}{5}=\frac{1}{2}$

$\frac{x}{y}=\frac{1}{2}+\frac{1}{5}$

$\frac{x}{y}=\frac{5+2}{10}$

$\frac{x}{y}=\frac{7}{10}ans.$

Solve part (c).

$\frac{x}{y}-\frac{1}{2}=\frac{1}{6}$

$\frac{x}{y}=\frac{1}{6}+\frac{1}{2}$

$\frac{x}{y}=\frac{1+3}{6}$

$\frac{x}{y}=\frac{4}{6}$

$\frac{x}{y}=\frac{2}{3}ans.$