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Question

Find a point on 6x - 5y = 4 whose ordinate is twice the abscissa.

A
(1, 2)
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B
(-1, -2)
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C
(2, 1)
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D
(-2, -1)
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Solution

The correct option is B (-1, -2)

Given, x=2y
Let the required point be (a, 2a)

Since it passes through the line, it will be a solution of the equation 6x – 5y = 4

Putting (a, 2a) in the equation, we get

6a – 10a = 4

-4a = 4

a = -1

The required point is (-1, -2)


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