Find a point on 6x - 5y = 4 whose ordinate is twice the abscissa.
Let the required point be (a, 2a)
Since it passes through the line, it will be a solution of the equation 6x – 5y = 4
Putting (a, 2a) in the equation, we get
6a – 10a = 4
-4a = 4
a = -1
The required point is (-1, -2)