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Question

Find a vector of magnitude 2 units and coplanar with vectors 3ijk and i+j2k and perpendicular to vector 2i+2j+k.

A
r=±15(3i+5j4k)
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B
r=±15(3i5j+4k)
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C
r=±14(2i2j+4k)
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D
r=±14(2i+2j4k)
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Solution

The correct option is B r=±15(3i5j+4k)
r=t{a×(b×c)} represents a vector coplanar with b and c and perpendicular to a.
r=t[(ac)b(ab)c]
Substitute the values of a.c and a.b
r=t(2b3c)=t[2(3ijk)3(i+j2k)]
r=t(3i5j+4k).
Take mod of both sides. |r|=|t|9+25+16
2=|t|.52 |t|=15t=±15
Required vector is ±15(3i5j+4k)

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