Find all the common zeroes of the polynomials x3+5x2−9x−45 and x3+8x2+15x.
-5
Let p(x)=x3+5x2−9x−45
q(x)=x3+8x2+15x
p(x)=x3+5x2−9x−45
p(x)=x2(x+5)−9(x+5)
p(x)=(x+5)(x2−9)
p(x)=(x+5)(x+3)(x−3)
⇒ Zeroes are -5,-3 and 3.
q(x)=x3+8x2+15x
q(x)=x(x2+8x+15)
q(x)=x(x+5)(x+3)
⇒ Zeroes are 0, -5 and -3
Therefore, common zeroes are -5 and -3.