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Question

The common zeroes of the polynomials x3+5x29x45 and x3+8x2+15x are:


A

0 , -5

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B

-5, 3

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C

-5,-3

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D

3,-3

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Solution

The correct option is C

-5,-3


x3+8x2+15x simplying this expression we get, x (x+3) (x+5) = 0, the value for x will be 0,-3,-5.

Substituting these values for x in the first expression, we get to know that -3 and -5 satisfy the expressions. Hence, -3 and -5 are the common zeroes of the polynomial.


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