Given, z5=(1+i=√3)
=2∣∣∣12+i√32∣∣∣=2[cos(π3)+isin(π3)]
Here, r=2,ϕ=arg(z)=π/3,n=5
nth roots are given by r1/5[cos(ϕ+2kπn)+isin(ϕ+2kπn)]
z0=21/5⎡⎢
⎢⎣cosπ3+2(0)π5⎤⎥
⎥⎦+i⎡⎢
⎢⎣sinπ3+2(0)π5⎤⎥
⎥⎦
z0=21/5(cosπ15+isinπ15)
z1=21/5⎡⎢
⎢⎣cosπ3+2π5+isinπ3+2π5⎤⎥
⎥⎦=21/5∣∣∣cos7π15+isin7π15]
z2=21/5⎡⎢
⎢⎣cosπ3+4π5+isinπ3+4π5⎤⎥
⎥⎦=21/5∣∣∣cos13π15+isin3π15]
z3=21/5[cos19π15+isin19π15] [ putting k=3 ]
z4=21/5[cos25π15+isin25π15] [ putting k=4 ]
z4=21/5∣∣∣cos5π3+isin5π3∣∣∣
z0,z1,z2,z3,z4 are the fifth roots of given complex no.