Question

Find an anti derivative (or integral) of the given function by the method of inspection.
$\sin 2x-4e^{3x}$

Answer 1

We know that,
$\frac{d}{dx}(-\frac{1}{2}\cos 2x-\frac{4}{3}{e}^{3x})=\sin 2x-4e^{3x}$
Therefore, the anti derivative of $(\sin 2x-4e^{3x})$ is $(-\frac{1}{2}\cos 2x-\frac{4}{3}{e}^{3x})$.