Find an anti derivative (or integral) of the given function by the method of inspection.
$sin 2 x$

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Solution

We know that,
$\frac{d}{d x} (cos 2 x) = - 2 sin 2 x$
$\Rightarrow sin 2 x = - \frac{1}{2} \frac{d}{d x} (cos 2 x)$
$∴ sin 2 x = \frac{d}{d x} (- \frac{1}{2} cos 2 x)$
Therefore, the anti derivative of $sin 2 x$ is $- \frac{1}{2} cos 2 x$

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