Since AB || QR and PR is a transversal. ∠ QRP = ∠ ABP = 100^o #160; #160; #160; [Corresponding angles] ...

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Axioms

Find ∠ QRP

Question

Find $∠ Q R P$

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Solution

Since AB || QR and PR is a transversal.
$∠ Q R P = ∠ A B P = 100^{o}$ [Corresponding angles]

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△ A B C \sim △ Q R P, \frac{a r (△ A B C)}{a r (△ Q R P)} = \frac{9}{4}

B C = 15 c m

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Δ A B C \sim Δ Q R P, a n (\frac{Δ A B C}{Δ Q R P}) = \frac{9}{4}

A B = \frac{9}{4},

A B = 18,

B C = 15 c m

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△ A B C a n d △ Q R P, A B = Q R, ∠ B = ∠ R a n d ∠ C = ∠ P .

△ A B C

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