Find area of trapezium whose parallel sides $9 c m$ and $5 c m$ respectively and the distance between these sides is $8 c m$ .

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Solution

Given: Length of parallel sides are $9$ cm and $5$ cm
Height $= 8$ cm
Area of trapezium $= \frac{1}{2} \times$ Height $\times$ (Sum of parallel sides)
$= \frac{1}{2} \times 8 c m \times (9 + 5) c m$
$= \frac{8 + 14}{2} c m^{2}$
$= 56 c m^{2}$ .

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Find area of trapezium whose parallel sides 9cm and 5cm respectively and the distance between these sides is 8cm.

Given: Length of parallel sides are 9cm and 5cmHeight =8cmArea of trapezium=12× Height ×(Sum of parallel sides)=12×8cm×(9+5)cm=8+142cm2=56cm2.

Find area of trapezium whose parallel sides $9 c m$ and $5 c m$ respectively and the distance between these sides is $8 c m$ .

Given: Length of parallel sides are $9$ cm and $5$ cm
Height $= 8$ cm
Area of trapezium $= \frac{1}{2} \times$ Height $\times$ (Sum of parallel sides)
$= \frac{1}{2} \times 8 c m \times (9 + 5) c m$
$= \frac{8 + 14}{2} c m^{2}$
$= 56 c m^{2}$ .