Find dy dx in terms of t- where x-a t 2 -y-at- t 3

x=a t ^ 2 and y= at t ^ 3 dx dt = 2at dy dt =a 2 t ^ 2 ⇒ #160; dy dx = a 2 t ^ 2 2at ...

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Parametric Differentiation

Find dy dx ...

Question

Find $\frac{d y}{d x}$ in terms of t, where
$x = a t^{2}, y = a t - t^{3}$

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Solution

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Similar questions

\frac{d y}{d x}

x = \frac{3 a t}{1 + t^{3}}, y = \frac{3 a t^{2}}{1 + t^{3}}

x = a t^{2}, y = 2 a t

\frac{d y}{d x} =

t \neq 0

x = a t^{2}, y = 2 a t

\frac{d y}{d x}

\frac{d y}{d x},

x = a t^{2}

y = 2 a t

\frac{d y}{d x} = x^{2} + 2 x + 4

y

x

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