Question

Find conjugate of:
$\sqrt{3}+\sqrt{2}$

• A. $\sqrt{3}-\sqrt{2}$
• B. $\sqrt{3}+\sqrt{2}$
• C. $\sqrt{3}\sqrt{2}$
• D. None of these

Answer 1

The correct option is A $\sqrt{3}-\sqrt{2}$

$\sqrt{3}+\sqrt{2}$
The procedure of multiplying a surd by another surd to get a rational number is called RationalisationThe operands are called rationalizing factor (RF) of the other
$(\sqrt{3}+\sqrt{2})\times (\sqrt{3}-\sqrt{2})={\sqrt{3}}^2-{\sqrt{2}}^2=9-4=5$
The Rationalizing factor of $\sqrt{3}+\sqrt{2}$ is $\sqrt{3}-\sqrt{2}$