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Question

Find cotAcotB+cotBcotC+cotCcotA.If A+B+C=π

A
1
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B
3
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C
4
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D
None of these
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Solution

The correct option is A 1
A+B+C=π
A+B=πC
tan(A+B)=tan(πC)
tanA+tanB1tanAtanB=tanC
tanA+tanB=tanC+tanAtanBtanC
tanA+tanB+tanCtanAtanBtanC=1
1cotA+1cotB+1cotC1cotAcotBcotC=1
cotAcotB+cotBcotC+cotCcotA=1

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