Question

Find $\frac{dy}{dx}$ for $y=e^x\left(a\cos x+b\sin x\right)$.

Answer 1

Given $y=e^x(acosx+bsinx)$

Now differentiating both sides

with respect to 'x' we get,

$\frac{dy}{dx}=e^x(acosx+bsinx)+$

$e^x(-asinx+bcosx)$