Find dydx if x-11-t2 and y-1-t2-

x=11 t^2 dxdt=(1 t^2)ddt(1) (1)ddt(1 t^2)(1 t^2)^2 #160; =(1 t^2)(0) (1)( 2t)(1 t^2)^2 #160; =2t(1 t^2)^2 #160; ∴dxdt=2t(1 t^2)^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Implicit Differentiation

Find dydx i...

Question

Find $\frac{d y}{d x}$ if $x = \frac{1}{1 - t^{2}}$ and $y = 1 + t^{2}$ .

Open in App

Solution

Suggest Corrections

Similar questions

x = \frac{1 - t^{2}}{1 + t^{2}}

y = \frac{2 t}{1 + t^{2}}

\frac{d y}{d x}

x

\frac{t^{2}}{1 + t^{2}}

y

\frac{2 a t}{1 + t^{2}}

\frac{d y}{d x}

x = \frac{1 - t^{2}}{1 + t^{2}}, y = \frac{2 t}{1 + t^{2}}

\frac{d y}{d x} = - \frac{x}{y}

x = \frac{1 - t^{2}}{1 + t^{2}}

y = \frac{2 a t}{1 + t^{2}}

\frac{d y}{d x}

x = \frac{3 a t}{1 + t^{2}}, y = \frac{3 a t^{2}}{1 + t^{2}}

\frac{d y}{d x}

Join BYJU'S Learning Program