Question

Find $\frac{dy}{dx}$
$y=\sin x.\cos x$

Answer 1

$y=\sin x\cos x\frac{dy}{dx}=\frac{d}{dx}\left(\sin x\cos x\right)\frac{dy}{dx}=\cos x\cos x+\sin x(-\sin x){\cos }^{2}x-{\sin }^{2}x\cos 2x$