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Byju's Answer
Standard XII
Mathematics
Algebra of Derivatives
Find ππ¦ππ₯...
Question
Find
d
y
d
x
when 𝑥 and 𝑦 are connected by the relation
t
a
n
−
1
(
x
2
+
y
2
)
=
a
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Solution
Given :
t
a
n
−
1
(
x
2
+
y
2
)
=
a
o
r
x
2
+
y
2
=
t
a
n
a
Differentiating both sides w.r.t. 𝑥 , We get,
d
d
x
(
x
2
+
y
2
)
=
d
d
x
(
t
a
n
a
)
⇒
2
x
+
2
y
.
d
y
d
x
=
0
[
∵
d
d
x
(
k
)
=
0
,
k
i
s
c
o
n
s
t
a
n
t
]
⇒
d
y
d
x
=
−
x
y
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0
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Standard XII Mathematics
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