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Question

Find ϕ[Ψ(x)] and Ψ[ϕ(x)] if ϕ(x)=x2+1 and Ψ(x)=3x.

A
Ψ[ϕ(x)]=3x2+1.
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B
ϕ[Ψ[x]]=32x+1
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C
Ψ[ϕ(x)]=3x3+1.
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D
ϕ[Ψ[x]]=3x+1
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Solution

The correct options are
A Ψ[ϕ(x)]=3x2+1.
B ϕ[Ψ[x]]=32x+1
ϕ[Ψ[x]]=ϕ(3x)=(3x)2+1=32x+1

and
Ψ[ϕ(x)]=Ψ(x2+1)=3x2+1.

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