Question

Find equation of line passing through (3,3) and (7,6) and length of intercept cut off by the axes

Answer 1

$\to$ Equation of line : $y-6=\frac{6-3}{7-3}(x-7)$

$\Rightarrow y-6=\frac{3}{4}(x-7)$

$\Rightarrow 4y-24=3x-21$

$\Rightarrow 4y=3x+3$

In Intercept form,

$4y=3x+3\Rightarrow 4y-3x=3$

$\Rightarrow \frac{4y}{3}-\frac{3x}{3}=1\Rightarrow \frac{y}{\left(3/4\right)}+\frac{x}{(-1)}=1$

length of intercepts = $\frac{3}{4}$ and $1$