Find equivalent resistance between A & B in the circuit:

$R_{1} + R_{2}$

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$R_{1} + R_{2} + R_{3}$

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$R_{1} + R_{3}$

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$R_{2} + R_{3}$

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Solution

The correct option is B
$R_{1} + R_{2} + R_{3}$

Components connected in series are connected along a single path so that same current flows through all of the components.
$∴ R_{1}, R_{2} & R_{3}$ are in series & we know,
For series, $R_{e q} = R_{1} + R_{2} + R_{3} + . . . . . . . . + R_{n}$
$∴ R_{e q} = R_{1} + R_{2} + R_{3}$

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