wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find dydxin the following questions:

sin2x+cos2y=1

Open in App
Solution

Given, sin2x+cos2y=1

Differentiating both sides w.r.t. x, we get

ddx(sin2x+cos2y=1)=ddx(1)

2 sin x cos x+2cos y(sin ydydx) (Using product ruleddx(f(g(x)))=f(x)ddxg(x))=0

2sin y cos ydydx=2sin x cos xdydx=sin 2xsin 2y=sin 2xsin 2y

( sin 2x=2sin x.cos x)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mathematical Induction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon