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Free Body Diagrams

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Question

Find friction force acting on block of mass $= 1 k g$ where $μ = 0.8$

6.8 N

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7 N

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6 N

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0 N

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Solution

The correct option is C $6 N$
$m g s i n θ = 1 \times 10 \times s i n 37 = 10 \times \frac{3}{5} = 6 N {(f_{s})}_{m a x} = μ N = 0.8 \times m g c o s θ = 6.4 N m g s i n θ < {(f_{s})}_{m a x} H e n c e b l o c k w i l l n o t m o v e f = m g s i n 37 f = 6 N$

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