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Byju's Answer
Standard XII
Mathematics
Integration by Parts
Find ∫0π/2si...
Question
Find
∫
π
2
0
sin
4
x
d
x
if
I
(
n
)
=
∫
π
2
0
sin
n
x
d
x
=
(
n
−
1
)
n
(
n
−
3
)
(
n
−
2
)
(
n
−
5
)
(
n
−
4
)
…
I
0
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Solution
∫
π
/
2
0
sin
n
x
d
x
=
n
−
1
n
n
−
3
n
−
2
.
.
.
.
.
π
2
∫
π
0
sin
4
x
d
x
=
3
4
1
2
π
2
=
3
π
16
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0
Similar questions
Q.
Assertion :The value of
∫
π
/
2
0
sin
6
x
d
x
=
5
π
16
Reason: If n is even, then
∫
π
/
2
0
sin
n
x
d
x
equals
n
−
1
n
n
−
3
n
−
2
n
−
5
n
−
4
.
.
.
1
2
×
π
2
Q.
If
I
=
∫
π
/
2
0
cos
n
x
sin
n
x
dx
=
k
∫
π
/
2
0
sin
n
x
dx
, then k equals