Find ${(3 x + 4 y)}^{2}$

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Solution

$(3 x + 4 y)^{2}$

$= (3 x)^{2} + 2 (3 x) (4 y) + (4 y)^{2}$

$= 9 x^{2} + 24 x y + 16 y^{2}$

$[∵ (a + b)^{2} = a^{2} = 2 a b + b^{2}]$

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Similar questions

a {(3 x - 4 y)}^{2} + 2 b (4 y - 3 x) = (m x - 4 y) (a (m x - 4 y) - 2 b)

m

{(3 x + 4 y)}^{2}

Factorise :

$(3 x - 4 y)^{2} - 25 z^{2}$

3 x + 2 y = 12

x y = 6

9 x^{2} + 4 y^{2}

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