Consider the given complex number,
z=3+4i
Now,
1z=13+4i
z−1=13+4i×3−4i3−4i
=3−4i32−16i2
∵i2=−1
∴z−1=3−4i32−16i2=3−4i32−16(−1)
z−1=3−4i25=325−4i25
Hence, this is the answer.
Given:(x+y+z)×(ab+1)=1
Find the value of z if x is additive inverse of y and a is multiplicative inverse of b.