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Question

find multiplicative inverse of (z)
z=3+4i then z1=?

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Solution

Consider the given complex number,

z=3+4i

Now,

1z=13+4i

z1=13+4i×34i34i

=34i3216i2

i2=1


z1=34i3216i2=34i3216(1)

z1=34i25=3254i25


Hence, this is the answer.


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