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B
√3×10−5T
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C
√32×10−5T
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D
3√3×10−5T
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Solution
The correct option is A2√3×10−5T Distance (r) of point P from wire is 8 cm (By pythagoras theorem) Bnet=2Bcosθ=2Bcos300 =2×2×√32×μ0i2πr =4×10−7×4√38×10−2=2√3×10−5T