Find out bond order in $N_{2}$ molecule and also draw the energy level diagram.

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Solution

$1 s^{2} 2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1} 2 p_{z}^{1}$
$σ 2 (2 s), σ^{*} 2 (2 s) π^{2} 2 p_{x} π^{2} 2 p_{y}, σ^{2} 2 p_{z}$
Bond Order $= \frac{1}{2}$ (Number of electrons in BO- Number of electrons in ABO)
$= \frac{1}{2} (8 - 2) = \frac{1}{2} (6) = 3$

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Find out bond order in N2 molecule and also draw the energy level diagram.

1s22s22p1x2p1y2p1zσ2(2s),σ∗2(2s)π22pxπ22py,σ22pzBond Order=12(Number of electrons in BO- Number of electrons in ABO)=12(8−2)=12(6)=3

Find out bond order in $N_{2}$ molecule and also draw the energy level diagram.

$1 s^{2} 2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1} 2 p_{z}^{1}$
$σ 2 (2 s), σ^{*} 2 (2 s) π^{2} 2 p_{x} π^{2} 2 p_{y}, σ^{2} 2 p_{z}$
Bond Order $= \frac{1}{2}$ (Number of electrons in BO- Number of electrons in ABO)
$= \frac{1}{2} (8 - 2) = \frac{1}{2} (6) = 3$