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Question

Find out how much does a43a2b2+b4 exceed 3a42a2b2+b4+3a2b+2ab2.

A
(2a4a2b2+3a2b2ab2)
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B
(2a4a2b23a2b2ab2)
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C
2a4a2b23a2b2ab2
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D
(2a4a2b23a2b2ab2)
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Solution

The correct option is D (2a4a2b23a2b2ab2)
To find out the resulting expression, we have to subtract (3a42a2b2+b4+3a2b+2ab2) from (a43a2b2+b4) as shown below:

(a43a2b2+b4)(3a42a2b2+b4+3a2b+2ab2)=a43a2b2+b43a4+2a2b2b43a2b2ab2

Collecting positive and negative like terms together, we get:

=a43a43a2b2+2a2b2+b4b43a2b2ab2=2a4a2b23a2b2ab2

Hence, the resulting expression is (2a4a2b23a2b2ab2).

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