Find out the correct relation for the dependance of change in acceleration due to gravity on the angle at the latitude due to rotation of earth?

d g \propto c o s ϕ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

d g \propto {c o s}^{2} ϕ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

d g \propto {c o s}^{3 / 2} ϕ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

d g \propto \frac{1}{c o s ϕ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $d g \propto {c o s}^{2} ϕ$
We know that, the effective gravity $g^{'}$ at a latitude $ϕ$ is given as
$g^{'} = g - ω^{2} R {(cos ϕ)}^{2}$
Thus, $g - g^{'} = d g = ω^{2} R {(cos ϕ)}^{2}$

Suggest Corrections

Similar questions

d g

In the given figure if $∠ G H E = ∠ D F E = 90^{\circ}$ , DH = 8 cm, DF = 12 cm, DG = 3x - 1 and DE = 4x + 2, then DG and DE are respectively ___.

A_{(g)} + B_{(g)} ⇌ C_{(g)} + D_{(g)}

A_{(g)} ⇌ C_{(g)} + D_{(g)}

A_{(g)} + B_{(g)} ⇌ D_{(g)}

f (x) = \frac{1}{\sqrt{| x | - x}}

g (x) = \frac{1}{\sqrt{x - | x |}}

A (g) + B (g) ⇌ C (g) + D (g),

K_{1}

C (g) + D (g) ⇌ A (g) + B (g),

K_{2} .

K_{1}

K_{2}

Join BYJU'S Learning Program